Math, asked by asunotoyeptho123, 6 months ago

Q1.A man goes 12m east and then 5m north.Find the
shortest distance from the starting point.
Q2. Two trees 9m and 4m high stands upright on a
ground,are 12m apart,then the distance between
their tops is.​

Answers

Answered by manjiribhumar7821
0

Step-by-step explanation:

Q1A have a look

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Answered by Anonymous
18

Answer:

ABC is right angled triangle ,

By Pythagoras property of triangle

AC² = BC² + AB²

AC² = 12² + 5²

AC²= 144 + 25

AC² = 169

AC²= 13²

AC = 13 cm

 Shortest distance from starting point = 13cm

sorry I don't know the 2nd answer

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