Math, asked by ishaawate9, 1 day ago

Q1: A man invests some money partly in 12% stock at 105 and partly in 8% stock at 88. To obtain equal dividends from both, he must invest the money in the ratio:

Answers

Answered by sanjai15102005
0

Answer:

Answer: Option D

Explanation:

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Solution 1

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In case of stock1, if he invest Rs.105, he will get a dividend of Rs.12 (assume face value = 100)

In case of stock2, if he invest Rs.88, he will get a dividend of Rs.8 (assume face value = 100)

ie, if he invest Rs.(88*12)/8, he will get a dividend of Rs.12

Required ratio = 105 : (88 × 12)/8 = 105 : (11 × 12) = 35 : (11 × 4) = 35 : 44

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Solution 2

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Let the amount of money he invest in 12% stock = P

Then, Number of shares = P/105 (where 105 is the market value per share)

Total dividend = (P/105) × 12 (Assume face value = Rs.100 and hence dividend per share = Rs.12)

Let the amount of money he invest in 8% stock = Q

Then, Number of shares = Q/88 (where 88 is the market value per share)

Total dividend = (Q/88)× 8 (Assume face value = Rs.100 and hence dividend per share = Rs.8)

If both needs to give equal dividends,

P

105

×

12

=

Q

88

×

8

P

Q

=

8

×

105

88

×

12

=

105

11

×

12

=

35

11

×

4

=

35

44

P:Q = 35:44

Step-by-step explanation:

Answered by MJarmygirl
0

Answer:

I don't know

Step-by-step explanation:

  1. sorry
  2. sorry
  3. sorry
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