Question

Q1 A man is watching the top of a 110 m
tower from the ground. He is standing at
a distance of 30m from the bottom of
the tower. Find the angle of elevation of
the tower with respect to the position of
the man.​

Answer 1

Step-by-step explanation:

Refer the image.

Thank you

Answer 2

The angle of elevation of the tower with respect to the position of the man is $74.74^{\circ}$.

Given,

Height of tower from ground = 110m

Distance of man from the bottom of the tower = 30m

To find,

Angle of elevation of the tower with respect to the position of the man.

Let us consider a right-angled triangle with,

Base = 30m

Perpendicular Height = 110m

The angle of elevation = $\theta$

We know that,

$tan\theta=\frac{Perpendicular}{Base}$

⇒ $tan\theta=\frac{110}{30}$

⇒ $tan\theta=3.67$

∴ $\theta = 74.74^{\circ$ .

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