Physics, asked by Anonymous, 12 days ago

Q1.A particle moves in a circle with
constant speed of 10 m/s. The radius
of the circle is 4m. The centripetal
acceleration of the particle will be -
---
O 25m/s^2
O 50m/s^2
O 200 m/s^2
O
400 m/s^2
in symbol​

Answers

Answered by oObrainlyreporterOo
11

Explanation:

Answer:

The centripetal acceleration of a particle moving in a circular motion is given by the formula:

\boxed{ \bf{a_c = \dfrac{v^2}{r}}} </p><p>

where,

'a' refers to centripetal acceleration, 'v' refers to velocity along the tangent, 'r' refers to the distance of the particle from the centre of rotation (also known as radius of the circular motion.)

According to the question,

v = 10 m/s

r = 4 m

Substituting the respective values we get:

\begin{gathered}\implies a_c = \dfrac{10^2}{4}\\\\\\\implies a_c = \dfrac{100}{4}\\\\\\\implies \boxed{ \bf{a_c = 25\:\:m/s^2}}\end{gathered} </p><p>⟹a </p><p>c</p><p>	</p><p> </p><p>

⟹a

c

=

4

100

[/tex]

⟹ </p><p>a </p><p>c</p><p>	</p><p> =25m/s </p><p> ^{2}

Hence Option (a) is the correct answer.

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