Question

Q1.A pebble thrown vertically upwards with an intial velocity 24m/s comes to rest in 6s. Find the decceleration.
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Answer 1

Step-by-step explanation:

SOLUTION

GIVEN

A pebble thrown vertically upwards with an initial velocity 24m/s comes to rest in 6s.

TO DETERMINE

The deceleration

EVALUATION

Here it is given that a pebble thrown vertically upwards with an initial velocity 24 m/s comes to rest in 6s.

Initial velocity = u = 24 m/s

Final velocity = v = 0

Time = t = 6 sec

Thus the required acceleration

$\displaystyle \sf{ = \frac{v - u}{t} }$

$\displaystyle \sf{ = \frac{0 - 24}{6} } \: \: m/{s}^{2}$

=-24/6 m/s²

$\displaystyle \sf{ = - 4 } \: \: m/{s}^{2}$

FINAL ANSWER

The deceleration = 4 m/s²

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