Question

Q1.a scooter acquires a velocity of 36 km per hour in 10 seconds just after the start.calculate the acceleration of the scooter. ​

Answer 1

Explanation:

✬ Acceleration = 1 m/s² ✬

Explanation:

Given:

Initial velocity of scooter is 0.

Final velocity of scooter is 36 km/h.

Time taken to attain final velocity is 10 seconds.

To Find:

What is the acceleration of the scooter ?

Formula to be used:

v = u + at

Solution: First change the km/h into m/s.

➟36 × 5/18

➟ 2 x 5

➟ 10 m/s

Now , we have

u = 0

v = 10 m/s

t = 10

Substituting the values on formula

⟹v = u + at

⟹ 10 = 0 + a × 10

⟹ 10 = 10a

⟹ 10/10 = a

⟹ 1 m/s² = a

Hence, the acceleration of scooter is 1 m/s².

Answer 2

Given:-

• Initial velocity of scooter, u = 0.
• Final velocity of scooter, v = 36 km/h.
• Time taken to attain final velocity, t = 10 seconds.

To Find:-

• What is the acceleration of the scooter ?

Solution:-

We are given :-

$\sf \green{:\implies Final\: velocity\: (u) = 36 \: km/h}$

$\sf \: \: \: \: \: \: \:\: \: :\implies Final \: velocity = 36\times \dfrac {5}{18}$

$\sf \: \: \: \: \: \: \:\: \: :\implies Final \: velocity =2\times 5$

$\sf\green{ \: \: \: \: \: \: \:\: \: :\implies Final \: velocity = 10\: m/s}$

$\small\underline{\pmb{\sf \:Using \: first \: equation \: of \: motion :-}}$

$\: \: \: \: \: \: \: : \implies \underline{ \boxed { \pink{{\frak{v = u + at}}}}}$

$\sf\: \: \: \: \: \: \: :\implies 10 = 0 + a × 10$

$\sf \: \: \: \: \: \: \: :\implies 10 = 10\times a$

$\sf \: \: \: \: \: \: \: :\implies \cancel{\dfrac{ 10}{10} }= a$

$\: \: \: \: \: \: \: : \implies \underline{ \boxed { \pink{{\frak{a =1\: m/s²}}}}}$

$\therefore\:\underline{\textsf{Acceleration of scooter is \textbf{1 m/s².}}}$