Question

Q1. A] Solve:
1. Find the perimeter of rectangle with length 15 cm and breadth 20 cm.
Ans:​

Answer 1

Answer :

• Perimeter of rectangle is 70cm

Given :

• Length = 15cm
• Breadth = 20cm

To find :

• Perimeter of rectangle

Solution :

As we know that,

• Perimeter of rectangle = 2(l + b)

Where , l is length 15cm and b is breadth 20cm

⇢ Perimeter of rectangle = 2(length + breadth)

⇢ 2(15 + 20)

⇢ 2(35)

⇢ 70cm

Hence , Perimeter of rectangle is 70cm

More Explanation :

• Rectangle has four vertices
• Rectangle has four edges
• Each internal angles is 90⁰
• Opposite sides are parallel and also equal length
• Area of rectangle = length × breadth
• Diagonal = √(l² + b²)

Answer 2

Given :-

• Length of Rectangle = 15cm
• Breadth of Rectangle = 20cm

To Find :-

• Perimeter of rectangle

Solution :-

❏ As we know that, Perimeter of Rectangle is given by [ Perimeter = 2 ( Length + Breadth ) ]

Putting the Values :

➞ Perimeter of Rectangle = 2 ( L + B )

➞ Perimeter of Rectangle = 2 ( 15 + 20 )

➞ Perimeter of Rectangle = 2 × 35

➞ Perimeter of Rectangle = 70cm

Thus Perimeter of Rectangle is 70cm

________________

Diagram :

$\tt20m \: \: \: \: \: \: \: \: \: \: \: \\ \red{\boxed{\begin{array}{}\bf { \red{}}\\{\qquad \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{}\\ { \sf{ }}\\ { \sf{ }} \\ \\ { \sf{ }}\end{array}}} \: \tt \: 15cm$

________________

★ Additional Info :

Formulas Related to Rectangle:

• Perimeter of Rectangle = 2( l + b)
• Area = Length × Breadth
• Length = Area / Breadth
• Breadth = Area / Length
• Diagonal = √(l)² + (b)²

________________