Math, asked by seemanouwar, 1 day ago

Q1
A triangular park ABC has sides 120m, 80m and 50m. A gardener Dhania has to puta
fence all around it and also plant grass inside. How much area in m²she need
to plant? ( and it's side AB = 50m , AC = 80m , BC = 120 and 3m in between for gate .)

(a) 9 √15
(5) 12√15
(c) 6 √15
(d) none of these

Answers

Answered by himab8420
1

Answer:

here, a=120m.

b = 80m ,

c = 50m

and, s =a+b+C/2=250/2=125

Area she need to plant grass=

√s (s-a) -a) (sb) (sc)

125 (125 – 120) (125-80) (125-50)

= 375√15m²

cost of fencing = [(a+b+c) -3].20

= [250-3].20

= R$4940

Answered by kingAeron
1

Answer:

here, a=120m,

b=80m,

c=50m

and, s=

2

a+b+c

=

2

250

=125

Area she need to plant grass =

s(s−a)(s−b)(s−c)

=

125(125−120)(125−80)(125−50)

=375

15

m

2

cost of fencing =[(a+b+c)−3].20

=[250−3].20

=Rs4940

Step-by-step explanation:

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