Question

Q1) ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (i)∆ABC~∆AMP (ii) CA/PA=BC/MP

Answer 1

Step-by-step explanation:

In △ABC and △AMP,

∠ABC=∠AMP=90

o

∠A is common

∴ By AA criterion of similarity, △ABC ∼ △AMP

∴

PA

CA

=

MP

BC

(Corresponding Sides of Similar Triangles)

Hence Proved