Question

Q1) ABC is an isosceles triangle ,AB=AC=12 cm. BC =10 cm. Calculate
the perpendicular distance from A to BC.

Answer 1

Step-by-step explanation:

ABC is an isosceles triangle

Given: AB=AC=12cm

BC = 10 cm

If we bisect BC then it divides BC in equally half and the mid point will be D

So, BD=DC=10/2=5cm

Triangle ABD is now right angled triangle.

AD= ?

Now,

hypotense^2=base^2+height ^2

(AB= hypotense,BD=base,AD=height)

or, 12^2=10^2 + AD^2

or, 144=100+AD^2

or, AD^2= 144 - 100

or, AD^2= 44

or, AD = rootover 44

or,AD= 2rootover 11= perpendicular distance