Math, asked by Bhaveshkr211, 9 days ago

Q1. Age of Sespo is three times the number x is 12. Age of Sespo's brother Sespe and his son Sesme is in ratio 4:2 respectively and the sum of their ages is 24 years. Age of Sesme's mom Sesle and his son Sesme is in ratio 5:3 and the sum of their ages if 48 years. Find their ages. And the sum of the ages of Sespo and his brother's age in ratio. And also find the difference among the ages of them?​

Answers

Answered by priyaranifeb2012
1

Answer:

3x+12=2(x+12)

3x+12=2x+24

x=12

Answered by brijeshkumarroy7026
1

Let the present age of son be x years

As per question the present age of father is three times

then present age of father is 3x

As per question after 12 years the age of father will be twice the age of son

3x+12=2(x+12)

⇒3x+12=2x+24

⇒3x−2x=24−12

⇒x=12

Then present age of son is 12 years

So present age of father =3×12=36 years

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