Q1. AM is a median of a triangle ABC, then
a) AB + BC + CA< 2AM
b) AB + BC + CA> 2AM
c) AB + BC + CA > AM
Q2. ABCD is a quadrilateral, then
a) AB + BC + CD + DA > AC +BD
b) AB + BC + CD +DA< AC + BD
C) AB + BC + CD + DA < AC - BD
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Answer:
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Answered by
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Answer:
1. AB + BC + CA> 2AM
2. AB + BC + CD + DA < AC - BD
Step-by-step explanation:
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