Q1 Among 5 objects P, Q, R, S and T
i. R is twice as heavy as T
ii. S is one and half times as heavy as Q
iii. Q and R together weigh as much as S and T together
iv. P and S together are one and half time as heavy as Q and T together
Which among the five is the heaviest of all?
A. Q
B. S
C. P
D. R
Answers
Answer:
S
Step-by-step explanation:
Given :- Among 5 objects P, Q, R, S and T :-
i. R is twice as heavy as T
ii. S is one and half times as heavy as Q
iii. Q and R together weigh as much as S and T together
iv. P and S together are one and half time as heavy as Q and T together .
Which among the five is the heaviest of all ?
A. Q
B. S
C. P
D. R
Solution :-
i. R is twice as heavy as T,
→ R = 2T --------- Eqn.(1)
ii. S is one and half times as heavy as Q,
→ S = (3/2)Q --------- Eqn.(2)
iii. Q and R together weigh as much as S and T together ,
→ Q + R = S + T --------- Eqn.(2)
putting value of Eqn.(1) and Eqn.(2) in Eqn.(3)
→ Q + 2T = (3Q/2) + T
→ 2T - T = (3Q/2) - Q
→ T = (Q/2)
→ Q = 2T --------- Eqn.(4)
now, putting Eqn.(4) in Eqn.(2) ,
→ S = (3/2) * 2T
→ S = 3T ---------- Eqn.(5)
iv. P and S together are one and half time as heavy as Q and T together ,
→ P + S = (3/2)[Q + T]
→ 2(P + S) = 3(Q + T)
putting value of Eqn.(4) and Eqn.(5),
→ 2P + 2 * 3T = 3 * 2T + 3T
→ 2P + 6T = 6T + 3T
→ 2P = 3T
→ P = (3/2)T
we get,
- P = (3/2)T
- S = 3T
- Q = 2T
- R = 2T
therefore,
→ 3T > 2T = 2T > (3/2)T > T
→ S > Q = R > P > T .
Hence, we can conclude that, Option (B) S is the heaviest of all .
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