Math, asked by harish13243, 2 months ago

Q1 Among 5 objects P, Q, R, S and T
i. R is twice as heavy as T
ii. S is one and half times as heavy as Q
iii. Q and R together weigh as much as S and T together
iv. P and S together are one and half time as heavy as Q and T together
Which among the five is the heaviest of all?
A. Q
B. S
C. P
D. R​

Answers

Answered by nibeditakoyel09
1

Answer:

S

Step-by-step explanation:

Answered by RvChaudharY50
3

Given :- Among 5 objects P, Q, R, S and T :-

i. R is twice as heavy as T

ii. S is one and half times as heavy as Q

iii. Q and R together weigh as much as S and T together

iv. P and S together are one and half time as heavy as Q and T together .

Which among the five is the heaviest of all ?

A. Q

B. S

C. P

D. R

Solution :-

i. R is twice as heavy as T,

→ R = 2T --------- Eqn.(1)

ii. S is one and half times as heavy as Q,

→ S = (3/2)Q --------- Eqn.(2)

iii. Q and R together weigh as much as S and T together ,

→ Q + R = S + T --------- Eqn.(2)

putting value of Eqn.(1) and Eqn.(2) in Eqn.(3)

→ Q + 2T = (3Q/2) + T

→ 2T - T = (3Q/2) - Q

→ T = (Q/2)

→ Q = 2T --------- Eqn.(4)

now, putting Eqn.(4) in Eqn.(2) ,

→ S = (3/2) * 2T

→ S = 3T ---------- Eqn.(5)

iv. P and S together are one and half time as heavy as Q and T together ,

→ P + S = (3/2)[Q + T]

→ 2(P + S) = 3(Q + T)

putting value of Eqn.(4) and Eqn.(5),

→ 2P + 2 * 3T = 3 * 2T + 3T

→ 2P + 6T = 6T + 3T

→ 2P = 3T

→ P = (3/2)T

we get,

  • P = (3/2)T
  • S = 3T
  • Q = 2T
  • R = 2T

therefore,

→ 3T > 2T = 2T > (3/2)T > T

→ S > Q = R > P > T .

Hence, we can conclude that, Option (B) S is the heaviest of all .

Learn more :-

Anu, Binu, Chinu, Dinu, Enu, Felu & Ganu are sitting facing towards east. Chinu is just right of Dinu. Binu is at one of...

https://brainly.in/question/27749189

Seven people from A to G sit on a horizontal bench in a specific order all of

them are facing north C is an immediate ne...

https://brainly.in/question/25457891

Similar questions