Question

Q1. Among 5 objects P, Q, R, S and T
i. Ris twice as heavy as T
IN
ii. S is one and half times as heavy as Q
iii. Q and R together weigh as much as S and T together
iv. P and S together are one and half time as heavy as Q and T together
Which among the five is the heaviest of all?
A. Q
B.S
C.P
D. R​

Answer 1

Answer:

option D

R is the heaviest.

Step-by-step explanation:

According to the given conditions :-

• R is twice as heavy as T

$R = 2 \: T$

• S is one and half times as heavy as Q

$S = 1 \frac{1}{2} \: Q$

• Q and R together weigh as much as S and T together

$Q + R = S + T$

• P and S together are one and half time as heavy as Q and T together

$P + S = 1 \frac{1}{2} (Q + T)$

Solution :-

Putting S = 3/2 Q and R = 2 T in 3rd condition , we get

Q + R = S + T

=> Q + 2T = 3/2 Q + T

=> Q + 3/2 Q = T - 2T

=> 5/2 Q = - T

=> Q = - 2/5 T = - 0.4 T

therefore , Q > T

Now ,

S = 3/2 × - 2/5 T = - 3/5 T = - 0.6 T

and

P = 3/2 ( Q + T ) - S

=> P = 3/2 ( - 2/5T + T ) -(- 3/5 T)

=> P = 3/2 ( -2+5/5 T ) + 3/5 T

=> P = 3/2 × 3/5 T + 3/5 T

=> P = 9/10 T + 3/5 T

=> P = 9+6/10 T

=> P = 15/20 T = 3/2 T = 1.5 T

• R = 2 T
• Q = -0.4T
• S = -0.6 T
• P = 1.5 T
• T = 1 T

$R > P > T > Q > S$

According to these values

R is the heaviest & S is the lightest.