Question

Q1) An element has 2 electrons in its N shell.
State its position in periodic table.
Q2) An element
$\frac{32}{16} s$
Give its formula with electronic configuration

Answer 1

Ans-1→ k shell can have 2 electrons
l shell can have 8 elctrons
m shell can have 18 electrons
n shell has 2 electrons

therefore its electronic configuration is 2,8,18,2

its atomic number will be 2+8+18+2=30

and since it has 4 shells then it means it will be in 4 rth period

Ans-2→ its atomic number is 16 .
therefore its electronic configuration will be 2,8,6.


hope it helps you