Physics, asked by dipenv33, 2 days ago

Q1. An elephant weighing 40,000 N stands on one foot of area 1000 cm^2 whereas a girl weighing 400 N is standing on one 'stiletto' heel of area 1 cm^1


(a) Which of the two,elephant or girl exerts a larger force on the ground?

(b)What pressure is exerted on the ground by the elephant standing on one one foot?

(c)What pressure is exerted on the ground by the girl standing on one foot?

(d)Which of the two,elephant or girl exerts a larger pressure on the ground?

(e)What is the ratio of pressure exerted by the girl to the pressure exerted by the elephant?

please can anyone help me with this?

Answers

Answered by starmoon22
1

Answer:

Weight of elephant=40000N

Area of one foot = 1000 cm

2

=1000×10

−4

m

2

Weight of girl=400N

Area of heel of girl = 1 cm

2

=1×10

−4

m

2

(a) Elephant has a larger weight of 40000N, therefore, elephant exerts a larger force on the ground. Elephant exerts a larger force on the ground by 40000N - 400 N = 39600 N.

(b) Weight of elephant = 40000N

Area of one foot = 1000 cm

2

=1000×10

−4

m

2

Pressure=

Area

Force

Pressure=

1000×10

−4

40000

=400000N/m

2

(c) Weight of the girl = 400N

Area of heel of girl =1 cm

2

=1×10

−4

m

2

Pressure=

Area

Force

Pressure=

1×10

−4

400

=4000000N/m

2

(d) Girl exerts a larger pressure on the ground.

(e) Ratio =

Pressure exerted by the elephant

Pressure exerted by the girl

=

400000

4000000

=

1

10

The pressure exerted by girl is 10 times greater than that exerted by the elephant.

Answered by Techoobant
7

Answer:

(a) The elephant exerts a larger force in the ground

(b) 40 pascal (P)

(c) 400 pascal (P)

(d) The girl exerts larger pressure on the ground

(e) 10 : 1

Explanation:

(a)

The elephant exerts larger force on the ground as it exerts the force of 40000 N whereas the girl exerts the force of 400 N on the ground.

(b)

Given,

Force exerted by elephant in the ground (F) = 40000 N

Area covered by it's foot (A) = 1000 square cm

We have,

Pressure exerted by elephant on the ground

= F / A = 40000 N / 1000 sq. cm

= 40 N / sq. cm

= 40 Pascal

Hence, the pressure exerted by elephant on the ground is 40 Pascal

(c)

Given,

Force exerted by the girl on the ground (F) = 400 N

Area covered by her foot (A) = 1 sq. cm

We have,

Pressure exerted by the girl on the ground =

= F / A

= 400 N / 1 sq. cm

= 400 Pascal

Hence, the pressure exerted by the girl on the ground is 400 Pascal (P).

(d)

The girl exerts more pressure than the elephant as we know pressure us inversely proportional to the surface area covered. That means if the surface area increases than the pressure decreases and vice versa. So since the pressure exerted by the girl on the ground is 400 pascal whereas the pressure exerted by elephant on the ground is 40 pascal, thus, the pressure exerted by the girl is more than that of elephant.

(e)

Given,

Pressure exerted by girl (P1) = 400 pascal

Pressure exerted by elephant (P2) = 40 pascal

We have,

Ratio = P1 / P2 = 400 pascal / 40 Pascal = 10 : 1

Therefore, the ratio of pressure exerted by the girl and the elephant is 10 : 1.

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