Q1 and Q2 please answer them
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(k-1)(-3)^2 +k(-3) +1=0
(k-1)9 -3k +1=0
9k-9-3k+1=0
6k-9= -1
6k=8
k=8/6
k=1/3
ujjwalgupta58:
and the next question please?
No, Since according to remainder theorem, degree of the remainder is less than the degree of divisor since in the second question degree of both the remainder and divisor is equal hence it's not possible.
thnks
bro the ans will be 4/3 cuz 8/6 when divided by 2 leads to 4/3
yeah sorry that's a typo
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Hope you get the help buddy
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