Question

Q1. Ashish is jogging at a speed of 5 km/h along a straight path. If the motion is uniform, what will be his speed after 10 seconds?

Answer 1

Answer:

?????

Explanation:

???? don't know what to do In this

Answer 2

$\it\red{\underline{\underline{Answer:}}}$

$\sf{Ashish's \ speed \ after \ 10 \ seconds \ will}$

$\sf{be \ 5 \ km \ hr^{-1}}$

$\it\orange{Given:}$

$\sf{\leadsto{Ashish \ is \ jogging \ at \ a \ speed}}$

$\sf{of \ 5 \ km \ h^{-1} \ along \ a \ straight \ path,}$

$\sf{the \ motion \ is \ uniform.}$

$\it\pink{To \ find:}$

$\sf{The \ speed \ of \ Ashish \ after \ 10 \ seconds.}$

$\it{\underline{\underline{Solution:}}}$

$\sf\blue{Concept:}$

$\sf{For \ object \ moving \ in \ uniform \ motion}$

$\sf{acceleration \ is \ zero.}$

$\sf{Here,}$

$\sf{\longmapsto{Initial \ velocity(u)=5 \ km \ hr^{-1}}}$

$\sf{\longmapsto{Acceleration (a)=0}}$

$\sf{\longmapsto{Time(t)=10 \ s=0.0028 \ hr(approx)}}$

$\sf{According \ to \ first \ equation \ of \ motion}$

$\boxed{\sf{v=u+at}}$

$\sf{\leadsto{v=5+0\times0.0028}}$

$\sf{\leadsto{v=5 \ km \ h^{-1}}}$

$\sf\purple{\tt{\therefore{Ashish's \ speed \ after \ 10 \ seconds \ will}}}$

$\purple{\tt{be \ 5 \ km \ hr^{-1}}}$