Question

Q1 Base=10cm Height=12cm Find Area

Q2 Find Base Height 5m Area 100m2

Q3 Base 5.2 mm Find Height Area 50.96mm2

These Are Indivisual Questions

Answer 1

Answer:

$\huge{\pink{\boxed{\green{\sf{(1)AREA=60cm^{2}}}}}}$

$\huge{\pink{\boxed{\green{\sf{(2)BASE=40m}}}}}$

$\huge{\pink{\boxed{\green{\sf{(3)HEIGHT=19.6mm}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

☆ FIRST QUESTION :

$\: \: \: \: \: \: { \orange{given}}\\ {\pink{\boxed{\green{height = 12cm}}}} \\ { \pink{ \boxed{ \green{base = 10cm}}}}\\ \\ \to area \: of \: triangle = \frac{1}{2} \times base \times height \\ \to area = \frac{1}{2} \times 10 \times 12 \\ \to area = 12 \times 5 \\ { \pink{\boxed{ \green{\to area = 60cm ^{2} }}}}$

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☆ SECOND QUESTION :

$\: \: \: \: \: { \orange{given}}\\ {\pink {\boxed {\green{height = 5m}}}} \\ {\pink {\boxed {\green{area = 100 {m}^{2} }}}} \\ \\ \to area \: of \: triangle = \frac{1}{2} \times base \times height \\ \to 100 = \frac{1}{2} \times base \times 5\\ \to 200 = base \times 5 \\ \to base = \frac{200}{5} \\ { \pink{ \boxed{ \green{\to base = 40m}}}}$

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☆ THIRD QUESTION :

$\: \: \: \: \: { \orange{given}} \\ { \pink{ \boxed{ \green{base = 5.2mm}}}} \\ { \pink{ \boxed{ \green{area = 50.96}}}} \\ \\ \to area \: of \: triangle = 50.96mm^{2} \\ \to \frac{1}{2} \times base \times height = 50.96 \\ \to \frac{1}{2} \times 5.2 \times height = 50.96 \\ \to height = \frac{50.96 \times 2}{5.2} \\ {\pink {\boxed {\green{\to \: height = 19.6mm}}}}$

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