Question

Q1. Calculate the current drawn from the battery by the network of resistors s
shown in figure
V​

Answer 1

Answer:

2 Ampere.

Explanation:

The given circuit is a balanced wheatstone bridge .  For this to be balanced ,

Ratio \fra$c{R₁}{R₂}$ = \fra$c{R₃}{Rₓ}$

                   Here in this case it is satisfying , therefore current doesn't flow through the 5Ω resistor .

               So we can remove it , this will not change anything in the circuit.

Here 1Ω and  2Ω are in series , and same goes with 2Ω  and 4Ω .

They become 3Ω  and 6Ω  which make a parallel combination .

Therefore the equivalent resistance of the circuit is 2Ω .

By using the relation  V = I*R

we get     4 = I*2

From that I = 2 Ampere