Question

Q1.Calculate the distance at which an object should be placed in front of a thin convex lens cap of focal length 10cm to obtain a virtual image of double its size?​

Answer 1

Answer:

Explation

height of image = 2 * height of object

magnification=+2 (virtual image)

m=v/u

2=v/u

v=2u

1/f=1/v-1/u

1/10=1/2u-1/u

1/10= -1/2u

-2u=10

u=-5cm