Q1. Calculate the molecular mass of the following:
[ Atomic mass of H= 1u, N=14u, O=16u, C=12u]
(a) HNO3 (b) CH2COOH
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Answer:
(a) molecular mass of (HNO3) = 1 × atomic mass of H + 1× atomic mass of N + 3× atomic mass of O
= 1×1 + 14×1 +16×3
= 63u
(b) molecular mass of (CH2COOH) = 1× atomic mass of c + 2 × atomic mass of H +1× atomic mass of C + 1× atomic mass of O + 1× atomic mass of O + 1× atomic mass of H
= 1×12 + 2×1 + 1×12 + 1×16 + 1×16 + 1×1
= 59u
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