Q1. Define :
(a) One cal.
(b)One kcal.
(c) Specific heat
(d)Humidity
(e) Low point temperature
(f) Relative humidity
Q2. How much heat energy is necessary to raise the temperature of 5 kg of water from
20°C to 100°C.
Q3. Equal heat is given to two objects A and B of mass 1 g. Temperature of A increases by
3°C and B by 5°C. Which object has more specific heat? And by what factor?
please solve it
it is urgent
Answers
Answer: 1:The calorie was originally defined as the amount of heat required at a pressure of 1 standard atmosphere to raise the temperature of 1 gram of water 1° Celsius.
2:A unit of energy measurement representing the amount of heat required to raise the temperature of one kilogram of water by 1°C.
3:The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.
4:Humidity is the amount of water vapor in the atmosphere. Water vapor is the invisible presence of water in its gaseous state.
5:The dewpoint temperature is the temperature at which the air can no longer "hold" all of the water vapor which is mixed with it, and some of the water vapor must condense into liquid water
Answer:
(1) a) calorie is defined as the amount of heat required at a pressure of 1 standard atmosphere to raise the temperature of 1 gram of water 1° Celsius. Its is also known as joule. one calorie is equal to approximately 4.2 joules.
b) The large calorie, food calorie, or kilocalorie is the amount of heat needed to cause the same increase in one kilogram of water. Thus, 1 kilocalorie = 1000 calories.
c) The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.
d) Humidity is the concentration of water vapour present in the air.
e) Dew point temperature is the minimum temperature at which dews of vapour are formed when a gas-vapour mixture is cooled at constant pressure.
f) Relative humidity is the ratio of the partial pressure of water vapor to the equilibrium vapor pressure of water at a given temperature.
(2) The formula is mass *Specific heat capacity * Temperature difference
= 5 (kg) * 4181 (J/kg °C) * (100–20) = 1672.4 KJ
