Question

Q1. Determine whether given equation is quadratic or not.  
(k+2)(k-5)=0.

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Answer 1

Answer:

this is your answer !!!

Answer 2

Answer:

(k+2)(k-5)=0

k(k-5)+2(k-5)=0

k²-5k+2k-10=0

k²-3k-10=0

it is in the form ax²+bx+c =0

were , a= 1 , b = -3 and c = -10

hence , it is a quadratic equation