Question

Q1. divide : (30x-6x^2-28) by (3x-4)

Q2. if (x+y)=14and xy =12, find the value of x^2+y^2​

Answer 1

Answer:

Q2= (x+y) = 14 ( given)

xy= 12 ( given)

(x+y)2 = x2+y2+2xy

(14)2= x2+y2+2*12

196= x2+y2+ 24

196-24 = x2+ y2

174= x2+y2

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