Question

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1)An elevator descends into a mine shaft at the rate of 5m / min. If the descent starts from 8 m above the ground level ,how long will it take to reach 42 m (means -42 m)below the ground level? ​

Answer 1

Answer:

10 minutes

Step-by-step explanation:

Given,

speed = 5m/min

total distance= (42m + 8m) =50m

(since, the descent starts from 8m above the ground level and have to travel 42m ( or -42m) below the ground level)

now since,

time = distance/speed =50/5= 10 min.

therefore,

the elevator will take 10 minutes to reach 42m below the ground level if it starts descent from 8m above the ground level.

Answer 2

To find:

Time taken to reach 42 m below the ground level (means - 42 m)

Step-by-step explanation:

Since the elevator starts from 8 m above the ground level, the distance between 8 m above the ground level and 42 m below the ground level is 8 - (- 42) = 8 + 42 = 50 m

Here the speed of the elevator is 5 m/min

Thus the required time

= total distance ÷ speed of the elevator

= 50 ÷ 5 min

= 10 min

Answer:

It will take 10 minutes to reach 42 m below the ground level.

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An elevator descends into a mine shaft at the rate of 5 m/min. If the descent starts from 8m above the ground level, how long will it take to reach 42 m (means -42 m) below the ground level ?

- https://brainly.in/question/47192355