Q1. Draw the shape of velocity-time graph of a uniformly accelerated motion of a body. (1)
Q2. Derive the velocity-position equation of motion (S = ut + ½ at2) graphically (with the help of a velocity-time graph) . (3)
Q3. The break applied to a car produce an acceleration of 6 m/s2 in the opposite direction to the motion. If the car takes two seconds to stop after the application of breaks, calculate the distance it travels during this time. (3)
Q4. (a)A body is moving in such a way that magnitude of velocity does not change but direction changes Can we say that it is accelerated motion? Give reason for your answer
(b) Define uniform circular motion. (2+1)
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Answer:A body is moving at a speed of 10m/s. After applying brakes, it accelerates uniformly in the opposite direction of motion and comes to rest in 10 seconds. What will be the distance covered during that time from the velocity time graph?
The distance that a body covers during time, t, is equal to the area between the velocity graph and the time axis. If this area is a triangle, the area is equal to the average height (velocity) multiplied by the width, t.
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