Question

Q1. Factorise. a(x-10)+b(10-x)
a. (x-10)(a-b)
b. (x+10)(a+b)
c. (x+10)(a-b)
d. (x-10)(a+b)

Q2. Factorise. 18a^2-48ab+32b^2
a. 2(3a-4b)(3a+4b)
b. None of these
c. 2(3a-4b)(3a-4b)
d. 2(3a+4b)(3a-4b)

Answer 1

Answer:

1. option a

2. option c

Step-by-step explanation:

1. ax-10a+10b-bx

=ax-bx-10a+10b

=x(a-b)-10(a-b)

=(x-10)(a-b)

option a

__________________________

2. 18a²-48ab+32b²

= 18a²-24ab-24ab+32b²

=6a(3a-4b)-8b(3a-4b)

=(3a-4b)(6a-8b)

=2(3a-4b)(3a-4b)

option c

Answer 2

Step-by-step explanation:

Q1 none

Q2 none

$a(x - 10) + b(10 - x) \\ ax - 10a + 10b - bx \\ a( x - 10) + b(10 - b) \\ \\ 18a {}^{2} - 48ab + 32b {}^{2} \\ 2(9a {}^{2} - 24ab + 16 {}^{2} ) = 0\\ 9a {}^{2} - 24ab + 16 {b}^{2} \\ (3a - 4b) {}^{2}$

I hope it helps you..................