Question

Q1. Factorise these. ​

Answer 1

Answer:

a) 2y^2-22y+48

=2(y^2-11y+24)

=2(y^2-8y-3y+24)

=2{y(y-8)-3(y-8)}

=2(y-8)(y-3)

b) -2x^2-x+6

= -2x^2-4x+3x+6

= -2x(x+2)+3(x+2)

=(x+2)( -2x+3)

=(x+2)(3-2x)

Answer 2

Step-by-step explanation:

a) 2( y²-11y+24)

= 2[(y²-8y-3y+24)]

= 2[y(y-8)-3(y-8)]

= 2(y-8)(y-3). Ans.

b) -2x²-4x+3x+6

= -2x(x+2)+3(x+2)

= (x+2)(3-2x) Ans.

this two are correct answer.