Question

Q1) Find a Pythagorean Triplet in which one member is 15??
(Explain) please ​

Answer 1

Answer:

8,15,17

Step-by-step explanation:

2m, m'2-1,m'2+1;

put the values and there you are!

Answer 2

Answer:

8, 15, and 17

Step-by-step explanation:

Given:- One of the triplets is 15

To find:- other 2 numbers of the triplet

Proof:-

We know that Pythagorus theorem is of the form

2m, m² - 1 and m² + 1

where m is an integer but not negative

Now, we know that out 2m, m² - 1, m² + 1 one of these must be equal to 15

Because 15 is one of the other triplets

So, let's find which corresponds to 15 and thus finding the value of 'm'

Let's say,

2m = 15, then

m = 15/2

But we said that m is an integer which is not negative

so, 2m isn't equal to 15

Now, let's say

m² - 1 = 15 then

m² = 15 + 1 = 16

m = 4

I am not taking negative because I said that m is an integer which is not negative so, m = 4

Now, we can use m = 4 to set up the triplets

2m = 2 × 4 = 8

m² - 1 = 4² - 1 = 16 - 1 = 15

m² + 1 = 4² + 1 = 16 + 1 = 17

So, the Pythagorean triplets in which one member is 15 are

8, 15, and 17

Hope it helped and you understood it........All the best