Question

Q1) Find the degree of polynomial :-

a) p(x)=(x+2) (x-2)


b) p(y)=(y³-3) (y²+1)



Q2) if p(x) = x³-3x²-2x +4 find p(2) +p(-2) -p(0)​

Answer 1

Answer:

1.a) degree =2

b) degree=5

Step-by-step explanation:

2.p(2)=2³-3.2²-2.2+4=8-3.4-4+4=8-12=-4

p(-2)=-2³-3.-2²-2.-2+4=-8.-12+8=-12

p(0)=0³-3.0²-2.0+4=4

-4+4-12=-12

I guess your final answer will be -12

Answer 2

Answer:

a) degree is 2

b) degree is t

Q2)-18

Step-by-step explanation:

p(2)=8-3(4)-4+4

=8-12-4+4

=-4

p(-2)=-8-12+4+4

-12

p(0)=0-0+4=4

p(2)+p(-2)-p(0)=-4-12-4=-18