Q1.find the distance between p(-3,4) and Q (1,-2)
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Explanation:
Here ,the two point is given and we have to find the distance between these points.For this we use distance formula for finding the distance.
Distance formula
Distance formulaD=√(x₂- x₁)²+(y₂- y₁)²
Distance between P and Q
P (-3,4) & Q( 1,-2)
x₁=-3;x₂ = 1 ; y₁= 4 & y₂ = -2
By using distance formula :
Distance between the point P&Q
PQ=> √ (x₂- x₁)²+(y₂- y₁)²
PQ=>√((1-(-3))²+(-2-4)²
PQ=>√(1+3)²+(-6)²
PQ=>√4²+(-6)²
PQ=>√ 16+36
PQ=>√52
PQ=2√13
Hence,the distance between P(-3,4)& Q(1,-2) is 2√13 units .
More information=>
Distance formula are used to find the distance between any two given points in XY plane only of the coordinates are known.
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