Question

Q1.find the domain of the real valued function f(x)=1/log(2-x)​.

Answer 1

Step-by-step explanation:

We have to find domain of the given function :-

$\rm \large f(x) = \dfrac{1}{log (2-x)}$

We know that denominator cannot be zero.

$\begin{gathered} \rm \longrightarrow log (2-x) \ne0 \\ \\ \rm \longrightarrow (2-x) \ne {e}^{0} \\ \\ \rm \longrightarrow 2-x \ne 1\\ \\ \rm \longrightarrow 2 - 1 \ne x\\ \\ \rm \longrightarrow 1 \ne x\\ \\ \rm \longrightarrow x \ne 1 \: \: \: \: ...(1)\end{gathered}$

Also,

$\begin{gathered} \large \rm \longrightarrow 2 - x > 0 \\ \\ \large \rm \longrightarrow 2 > x \: \: ...(2)\end{gathered} </p><p>$

From equation (1) and (2) :-

$\begin{gathered} \rm D_f = x \in (- \infty, 2) - \{1 \} \\ or \\ \rm D_f = x \in (- \infty, 1) \cup (1,2) \\ \\ \rm \: where \: D_f \: is \: domain \: of \: the \: function\end{gathered} </p><p>$