Question

Q1) Find the greatest number of 5-digits which on being divided by 9, 12, 24 and 45 leaves 3, 6, 18 and 39 as remainders respectively.

Answer 1

Answer:

97214

Step-by-step explanation:

FIRST TAKE THE LCM OF DIVISORS

LCM OF( 9,12,24,45) IS 360  

We know the largest five digit number is 99999

Now to find the largest five digit number which satisfy the given conditons then do the following

A) 360*N-6

N, is the quotient of 99999/360

U will get the answer as 360*277–6= 97214

B) Divide 99999/360

U will get remainder as 279

SUBTRACT 279 FROM 99999 WHICH IS 99720

Now 99720–6= 97214 which will be ur answer

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