Question

Q1) Find the maximum and minimum value of the function: x^3 - 3x^2 - 9x + 12​

Answer 1

Answer:

x= -12 , -21 , -18

Step-by-step explanation:

x³-3x²-9x+12= 0

${x}^{3} - 3 {x}^{2} - 9x = ( - 12) \\ x( {x}^{2} - 3x - 9) = - 12 \\ ans \: = \: \: \: \: x = - 12 \\ \\ {x}^{2} - 3x - 9 = - 12 \\ {x}^{2} - 3x = - 21 \\ x(x - 3) = - 21 \\ x = - 21 \\ x - 3 = - 21 \\ x = - 18$