Question

Q1.Find the median of the following data:Class 0 – 20 20 – 40 40 – 60 60 – 80 80 – 100 100 – 120 120 – 140Frequency 10 35 52 61 38 29

Answer 1

Step-by-step explanation:

Answer:

65.08

Step-by-step explanation:

$\begin{gathered}\left(\begin{array}{ccc}C.I.&Frequency&cf\\0-20&10&10\\20-40&35&45\\40-50&52&97\\60-80&61&158\\80-100&38&196\\100-120&29&225\\&N=225&\end{array}\right)\end{gathered}$

Now,

N/2 = 225/2 = 112.5

Since , the Commnulative frequency just greater than 112.5 is 158.

So, The class 60-80 is the median class,.

We have,

L= 60

cf = 97

h = 20

f = 61

Thus,

$\begin{gathered}\text{Median}=L+(\frac{\frac{n}{2}-cf}{f})\times h\\\;\\=60+(\frac{112.5-97}{61})\times20\\\;\\=65.08\end{gathered}$