Question

⠀
Q1. Find the principal value of $\sf{\sin\dfrac{151\pi}{6}}$.​

Answer 1

Answer:

Given

⇒ sin 4530° = 90° × 50 + 30°

4530° lies in the third quadrant in which the sine function is negative.

∴ sin 4530° = sin (90° × 50 + 30°)

= - sin 30°

= -1/2