Q1) find the product : (y+2) (y-2) (y^2+4) Q2) If 4a^2+b^2=40 and ab=6 , find the value of 2a+b.
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(y − 2 ) ( y + 4 ) First Term, = ( y − 2 ) ( y+4 ) Outer Term, = ( y − 2 ) ( y +4 ) Inner Term, = ( y − 2 ) ( y 4 ) Last Term, = ( y − 2 ) ( y^ + 4 )
If 4a^2+9b^2=97 and ab=6 , find the value of 2a+3b. The answer is 169
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