Question

Q1- Find the roots of root2 x square -3x-2 root 2 =0 by completing the square method?

Answer 1

Answer:

$\sqrt{2}x^2-3x-2\sqrt{2}=0\\\\\sqrt{2}(x^2-\frac{3}{\sqrt{2}}x-2)=0\\\\\sqrt{2}(x^2-\frac{3}{\sqrt{2}}x+\frac{9}{8})-2\sqrt{2}-\frac{9}{4\sqrt{2}}=0\\\\(x-\frac{3}{2\sqrt{2}})^2=\frac{25}{8}\\\\x-\frac{3}{2\sqrt{2}}=\frac{5}{2\sqrt{2}}\\\\x=2\sqrt{2}\\\\x-\frac{3}{2\sqrt{2}}=-\frac{5}{2\sqrt{2}}\\\\x=-\frac{1}{\sqrt{2}}$

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