Q1)Find the value of k if the points A=(8,1) B = (3,-4)
c = (2, K) are collines. [K= - 5]
Q2) Find the value of K if the points A=(K, 3) B=(6,-2) and
c = (-3,4) are colleras. [K= -3/2]
pls answer this step by step
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Answer:
Since the given points are collinear, they do not form a
triangle, which means area of the triangle is Zero.
Area of a triangle with vertices (x1,y1) ; (x2,y2) and (x3,y3) is ∣∣∣∣2x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣∣∣∣
Hence, substituting the points (x1,y1)=(8,1) ; (x2,y2)=(k,−4) and (x3,y3)=(2,−5)
the area formula, we get
∣∣∣∣28(−4+5)+k(−5−1)+2(1+4)∣∣∣∣=0
=
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Answer:
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