Math, asked by willukissme, 14 days ago

Q1.Find the value of: tan10, tan20,………..tan450,…………tan890

Answers

Answered by narayanrawal80
0

Step-by-step explanation:

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Answered by PRINCE100001
4

Step-by-step explanation:

SOLUTION

TO DETERMINE

The value of

\sf{ \tan {10}^{ \circ}. \tan {20}^{ \circ}. \: ... \:\tan {450}^{ \circ} \: \: .. \:\tan {890}^{ \circ} }

EVALUATION

We have to find the value of

\sf{ \tan {10}^{ \circ}. \tan {20}^{ \circ}. \: ... \:\tan {450}^{ \circ} \: \: .. \:\tan {890}^{ \circ} }

So the given expression

\sf{ = \tan {10}^{ \circ}. \tan {20}^{ \circ}. \: ... \:\tan {450}^{ \circ} \: \: .. \:\tan {890}^{ \circ} }

\sf{ \tan {10}^{ \circ}. \tan {20}^{ \circ}. \: .\tan {360}^{ \circ}.. \:\tan {450}^{ \circ} \: \: .. \:\tan {890}^{ \circ} }

Now

\sf{\tan {360}^{ \circ} }

\sf{ = \tan (4 \times {90}^{ \circ} + {0}^{ \circ} ) }

=tan0°

=0

Therefore

\sf{ \tan {10}^{ \circ}. \tan {20}^{ \circ}. \: ... \:\tan {450}^{ \circ} \: \: .. \:\tan {890}^{ \circ} }

\sf{ = \tan {10}^{ \circ}. \tan {20}^{ \circ}. \: .\tan {360}^{ \circ}.. \:\tan {450}^{ \circ} \: \: .. \:\tan {890}^{ \circ} }

=0

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