Q1. Find the zeroes of the polynomial f(x)= x 11x-12. Also verify the relationship between
zeroes and its coefficient.
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Answer:
Hopeit is helpful
Step-by-step explanation:
We have: f(x)=x2+3x−10 =x2+5x−2x−10 =x(x+5)−2(x+5) =(x−2)(x+5) ∴f(x)=0=>(x−2)(x+5)=0 =>x−2=0 or x+5=0 =>x=2 or x=−5 So, the zeroes of f(x)are 2 and−5. Sum of the zeroes = 2+(−5)= −3=
−3
1
=
−(coefficient of x)
(coefficient of x2)
Product of the zeroes= 2× (−5) = −10 =
−10
1
=
constant term
(coefficient of x2)
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