Question

Q1: How many bits would be needed to access a 32GB RAM?
Q2: What will be sum of -11 and 13 using 2’s complement?

Answer 1

Answer:

pata nhi

i donk know

我不知道

Explanation:

Non lo so

Answer 2

Q1: 4 giga bytes

Q2: -11 + 13

11 = 01011

13 = 01101

2's complement of 11 gives us -11

-11 = 10101

10101 + 01101 = 00010

[carry 1 is discarded]

In 00010 the MSB indicates the sign

Therefore, ans = 0010 [+2]