Question

Q1.)How much heat will be absorbed by 100gm of ice at 0⁰C is converted into water at 50⁰C.
Given:-latent heat of melting of ice is 80 cal/g.
specific heat of water=1 cal/g⁰C

Q2.)How much heat will be released when 200gm of steam at 100⁰C is converted into water at 80⁰C.
Given:-latent heat of steam=540 cal/g.​

Answer 1

Answer:

Here, Mass of water m

w

=100g

Mass of ice, m

i

=10g

Specific heat of water,S

w

=1calg

−1

o

C

−1

Latent heat of fusion of ice,L

fi

=80calg

−1

Let T be the final temperature of the mixture.

Amount of heat lost by water

=m

w

s

w

(△T)

w

=100×1×(50−T)

Amount of heat gained by ice

=m

i

L

fi

+m

i

s

w

(△T)

i

=10×80+10×1×(T−0)

According to principle of calorimetry:

Heat lost = Heat gained

100×1×(50−T)=10×80+10×1×(T−0)

500−10T=80+T

11T=420orT=38.2

o

C

Answer 2

Jekyll's and Mr. Hyde's handwriting. Sir Danvers Carew: A distinguished M.P. (Member of Parliament), who does not appear in the work, but whose unprovoked and vicious murder by Edward Hyde causes a turning point in the novel.