Question

Q1. How much mass of silvel nitrate
will react with 5.85 g of sodium
chloride to produce 14.35 g of silver
chloride and 8.5 g of sodium nitrate if
law of conservation of mass is
followed?​

Answer 1

Answer:

the answer is 1.70 grams for this question

Answer 2

Answer:

Hear is your answer.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

AgNO_3+NaClarrow AgCl+NaNO_3AgNO

3

+NaClarrowAgCl+NaNO

3

Given: mass of sodium chloride = 5.85 g

Mass of products = Mass of silver chloride + mass of sodium nitrate = 14.35 + 8.5 = 22.85 g

Thus mass of reactants = mass of silver nitrate + mass of sodium chloride = 22.85 g

Mass of silver nitrate + 5.85 g = 22.85 g

Mass of silver nitrate = 17 g

Thus mass of silver nitrate that will react is 17 grams.