Question

Q1.If log, (x2 + x) - log. (x + 1) = 2, then
(a) x = 2
(b) x = 4
(c) x = 5
(d) x = 16

Q2.The difference between simple interest of 12%
p.a. and compound interest of 12% p.a.
compounded half yearly on a sum of Rs. 3000
in one year is-
(a) Rs. 10.80 (b) Rs. 12.00
(c) Rs. 18.80 151 (d) Rs. 14.00
13.
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Answer 1

Answer:

Step-by-step explanation:

Q1.

log(x²+x)-log(x+1)=log(2)

⇒log{(x²+x)/(x+ 1)}=log(2)

⇒log{x(x+1)/(x+1)}=log(2)

⇒log(x)=log(2)

⇒x=2

Q2.

Simple Interest in 1 year - Compound Interest in 1/2 year

= (3000*12*1)/100 - 3000{(1+12/200)¹ - 1}

=(30*12) - 3000(12/200)

=360 - 30*6

=360 - 180

=180