Question

Q1. If Meena gives an interest of ₹ 45 for one year at 9% rate p.a.. What is the sum she has borrowed?​

Answer 1

Answer:

S.I=45 Rs

time =1 years

rate=9%

S.I= P×R×T/100

45=P× 9×1/100

P=45×100/9

P=4500/9

P=500Rs......

so the answer is 500Rs per annum....

Hope it's helpful to you

Answer 2

The sum borrowed is Rs.500.

Step-by-step explanation:

Given : If Meena gives an interest of Rs.45 for one year at 9% rate p.a.

To find : What is the sum she has borrowed ?

Solution :

Applying interest formula,

I= P*T*R

Where, I=Rs.45 is the interest

R=9%=0.09 is the interest rate

T=1 year is the time

P is the principal or sum

Substitute the value in the formula,

45 = p*0.09*1

P= 45/0.09

P= 500

Therefore, The sum borrowed is Rs.500.

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