Q1.If one root of the equation xsquare+7x+k=0 is -2, then find the value of k and the other root.
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one root of x²+7x+k = 0 is -2
therefore, (-2)² + 7(-2)+k = 0
4 - 14 + k = 0
k = 10
The equation is x²+7x+10 = 0
Product of the roots = αβ = 10
(-2) β = 10
β = -5
the other root is -5
therefore, (-2)² + 7(-2)+k = 0
4 - 14 + k = 0
k = 10
The equation is x²+7x+10 = 0
Product of the roots = αβ = 10
(-2) β = 10
β = -5
the other root is -5
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