Q1.If
\sec \theta \: + \tan \theta = \bf \: x
Then prove that
\sf \: sin \theta = \dfrac{ {x}^{2} - 1 }{ {x}^{2} + 1}
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Step-by-step explanation:
GIVEN :-
Sec∅ + tan∅ = x.
TO PROVE :-
Sin∅ = (x² - )/(x² + 1).
SOLUTION :-
Taking the RHS part,
Substitute the value of x,
Now as we know that , sec²A - 1 = tan²A.
Taking 2tanA as a common in numerator and 2secA in denominator,
As we know that , tanA = sinA/cosA and secA = 1/cosA,
Hence proved.
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