Q1. If
and
then evaluate 
Q2. If (x+a) is a factor of the polynomials
and
the prove: 
Answers
Answered by
2
see the attachment for soln.
Attachments:


Answered by
2
x² = 2 + √5 + 2 - √5 + 2 (2² - 5)
y² = 2 + √5 + 2 - √5 - 2 (4 - 5)
x²+y² = 8
x+a is a factor. So a² - p a + q = 0 and a² - m a + n = 0
Subtract one equation from another.
(m-p) a + (q-n) = 0
a = (n-q )/ (m-p)
y² = 2 + √5 + 2 - √5 - 2 (4 - 5)
x²+y² = 8
x+a is a factor. So a² - p a + q = 0 and a² - m a + n = 0
Subtract one equation from another.
(m-p) a + (q-n) = 0
a = (n-q )/ (m-p)
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